At a distance a from the foot of a tower AB of height b,a flag staff BC and the tower AB subtend equal angles. Prove that the height of the flag staff is b(a^2+b^2)/a^2-b^2.
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Answer:
a
b
=tanθ,
a
b+x
=tan2θ
or
a
b+x
=
1−tan
2
θ
2tanθ
=
1−
a
2
b
2
2.
a
b
a
b+x
=
a
2
−b
2
2ab
∴x=
a
2
−b
2
2a
2
b
−b
or x=
a
2
−b
2
a
2
b+b
3
=
a
2
−b
2
b(a
2
+b
2
)
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