At a distance d from a charge, the magnitude of the electric field is E. What would be the magnitude of the electric field a distance d/2 from the same charge?
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E' = 9*10^9 * q/(r)^2
E" = 9*10^9 * q/(r/2)^2
E" 4(9*10^9)q/r^2
E" = 4E'
E" = 9*10^9 * q/(r/2)^2
E" 4(9*10^9)q/r^2
E" = 4E'
charafbkm:
please can you answer the following question: A small metal ball with a mass of 10 grams and a charge of 5.0 mC is located in a region of space with an electric field of 12 N/C directed to the east. The ball is released from rest at a distance of 30 cm above the ground. What is the speed of the ball just before it hits the ground?
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