Question

AT a distance L=400m from the traffic light brakes are applied to a locomotive moving at a velocity v=54 km/hr. Determine the position of the locomotive relative moving to the traffic light 1 min after the application of the brakes if its acceleration is -0.3m/sec²?​

Answer 1

Answer:

25m

Explanation:

given,

distance l=400m

u=54kmph

a=-0.3m/s2

u=15mps

v=u+at

t=v-u/a

t=15s

avrage velocity=7.5m/s

distance s = 7.5/15=375m

total distance=400m-375m=25m

Thus 25 m before traffic light.

Hope your doubt is cleared.

Answer 2

Answer:

25 m

Explanation:

v=54 km/h

=(54*5)/18 =15 m/sec.

v^2=u^2+2aS

v=0 when the locomotive stops

0 =225-0.6S

S=(-2250)/(-6)

=375 m

Therefore, 400-375=25 m

So, the locomotive is at a distance of 25 m, 1 min after applying the breaks