Question

At a fete cards bearing numbers 1 to 1000 one number on one card are put in a box each player selects one card at random and that card is not replaced if the selected card has a perfect square number greater than 500 the player wins a prize what is the probability that (i) the first player wins the prize (ii) the second player wins a prize
if the first has won

Answer 1

Answer:

(i) 0.009

(ii) 0.008

Step-by-step explanation:

Total no. of cards = 1000

No. of cards having perfect squares greater than 500 in the set = 9

Probability = No. of favorable events / Total no. of possible events

(i) Probability of the first player to win = 9/1000 = 0.009

(ii) The card is not replaced, hence the total no. of possible choices for 2nd player is 999. Also, it is considered that first player wins. Hence the no. of favorable events is 8.

Probability that the second player wins = 8/999 = 0.008

Answer 2

Step-by-step explanation:

no. of cards having perfect square greater than 500 = 529,576,625,676,729,784,842,900,

961.

(I) p( first player win)=9/1000=0.009

(2)p(2nd player win)=8/999