at a function, the ratio of the number of men to the woman was 3: 4 . when another 5 men and 5 woman joined the function, the ratio became 7:9. how many men were there ay the function at first.
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Let the ration of men and women =x:y
Acceding to given question.
y
x
=
4
3
4x=3y
x=
4
3y
−−−−−−−−−−−(1)
Now,
5 men and 5 women joining the function.
So,
y+5
x+5
=
9
7
9x+45=7y+35
9x−7y=35−45
9x−7y=10
9x−7y+10=0−−−−−−−−−−−(2)
From equation (1) and (2) to
9×
4
3y
−7y+10=0
27y−28y+40=0
−y+40=0
−y=−40
y=40
Women =40
Put the value of y in equation (1) and we get
x=
4
3y
x=
4
3×40
x=3×10
x=30
Men =30
Hence, 30 men were there at the function at first.
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