At a garage sale, a large bin full of DVDs and CDs are being sold. All the DVDs are the same price, and all the CDs are the same price. Aleah buys 2 DVDs for $6 and 4 CDs for $8. Her friend, Ling, wants to buy 4 DVDs and 2 CDs. How much will Ling have to pay? Aleah's brother, Pierre, wants to spend $20 on DVDs and CDs. What combination of DVDs and CDs could he buy? 40 POINTS!!!!!!!!!!
Answers
Aиѕωєя:
❥Ling have to pay $16
❥combination of DVDs and CDs =
- ( 2 DVDs & 7 CDs)
- Or (4 DVDs & 4 CDs)
- Or (6 DVDs & 1 CD)
Given:
- All the DVDs are of same price
- All the CDs are of same price
To find:
- Cost for (4 DVDs + 2 CDs)
- combination of ( DVDs + CDs ) in 20$
☞ Since Aleah buys 2 DVDs for $6
Therefore,
cost of 1 DVD = 6/2 = 3$ ....(1)
ㅤㅤ[∵ Given- all DVDs have same price]
Similarly,
Cost of 1 CD = (Total cost/Total no. of CD)
⟹ Cost of 1 CD = 8/4 = $2 ...(2)
☞ using (1) and (2);
⟹Cost of 4 DVDs = 4×3 = 12$
⟹Cost of 2 CDs = 2×2 = 4$
∴ Cost of (4 DVDs + 2 CDs) = (12 +4 ) = 16$
Therefore, Ling have to pay $18, to buy 4 DVDs and 2 CDs.
☞ Total amount to spend = $20
Let Pierre buy 'x' DVDs and 'y' CDs.
Then,
- Cost of 'x' DVDs = 3*x = 3x
- Cost of 'y' CDs= 2*y = 2y
∴ 3x + 2y = 20
⟹ y = (20-3x)/2
❥{TRICK- since 2 is in denominator so, multiple of 2 will give the real values,other values will give in decimal form}
Forming the appropriate combinations :
if x=0, y = (20-0)/2 = 10 ✖
if x= 2, y = (20-6)/2 = 7 ✔
if x= 4, y = (20-12)/2 = 4 ✔
if x= 6, y = (20-18)/2 = 1 ✔
if x= 8, y = (20-24)/2 = -2 ✖
.
.
Therefore, Pierre can buy ( 2 DVDs & 7 CDs) or (4 DVDs & 4 CDs) or (6 DVDs & 1 CD) in $20.
▩━━━━━◈◈━━━━━▩
ㅤㅤ
❥
[Hey ya!! this is Pratush Gautam,there are many more questions like this which are answered.Pls check the profile or link below.
Don't forget to visit and give a ♡.
https://brainly.in/app/profile/19899637 ]
ㅤㅤ
ㅤㅤㅤㅤㅤㅤ
Step-by-step explanation:
Aиѕωєя:
❥Ling have to pay $16
❥combination of DVDs and CDs =
( 2 DVDs & 7 CDs)
Or (4 DVDs & 4 CDs)
Or (6 DVDs & 1 CD)
\Large\sf\pink{ \underline{{\rm{E}xplanation\rm{N}}}:}
ExplanationN
:
Given:
All the DVDs are of same price
All the CDs are of same price
To find:
Cost for (4 DVDs + 2 CDs)
combination of ( DVDs + CDs ) in 20$
\large\red ✿\large{\bold{\fbox{\red S}\fbox{\purple o}\fbox{\pink ℓ}\fbox{\orange u}\fbox{\green т}\fbox{\blue i}\fbox{\orange o}\fbox{\purple N}\large\red ✿}}✿
S
o
ℓ
u
т
i
o
N
✿
☞ Since Aleah buys 2 DVDs for $6
Therefore,
cost of 1 DVD = 6/2 = 3$ ....(1)
ㅤㅤ[∵ Given- all DVDs have same price]
Similarly,
Cost of 1 CD = (Total cost/Total no. of CD)
⟹ Cost of 1 CD = 8/4 = $2 ...(2)
\Large{\fcolorbox{grey}{yellow}{Part- \pink{i}}}
Part- i
☞ using (1) and (2);
⟹Cost of 4 DVDs = 4×3 = 12$
⟹Cost of 2 CDs = 2×2 = 4$
∴ Cost of (4 DVDs + 2 CDs) = (12 +4 ) = 16$
Therefore, Ling have to pay $18, to buy 4 DVDs and 2 CDs.
\Large{\fcolorbox{grey}{yellow}{Part- \pink{ii}}}
Part- ii
☞ Total amount to spend = $20
Let Pierre buy 'x' DVDs and 'y' CDs.
Then,
Cost of 'x' DVDs = 3*x = 3x
Cost of 'y' CDs= 2*y = 2y
∴ 3x + 2y = 20
⟹ y = (20-3x)/2
❥{TRICK- since 2 is in denominator so, multiple of 2 will give the real values,other values will give in decimal form}
Forming the appropriate combinations :
if x=0, y = (20-0)/2 = 10 ✖
if x= 2, y = (20-6)/2 = 7 ✔
if x= 4, y = (20-12)/2 = 4 ✔
if x= 6, y = (20-18)/2 = 1 ✔
if x= 8, y = (20-24)/2 = -2 ✖
.
.
Therefore, Pierre can buy ( 2 DVDs & 7 CDs) or (4 DVDs & 4 CDs) or (6 DVDs & 1 CD) in $20.
▩━━━━━◈\large \bf\mathfrak{ \underline{ \underline{\red{E}\green{N}\pink{D}}}}
END
◈━━━━━▩
ㅤㅤ
❥ \Large{\fcolorbox{green}{grey}{ \underline\red{note\pink ࿐}}}
note࿐
[Hey ya!! this is Pratush Gautam,there are many more questions like this which are answered.Pls check the profile or link below.
Don't forget to visit and give a ♡.
https://brainly.in/app/profile/19899637 ]
ㅤㅤ \: \: \Large\sf \purple{♡\underline{ \pink{{\rm{T}han\rm{K}}}}}♡
ThanK
\Large\sf \purple{\underline{ \pink{{\rm{Y}o\rm{U}}}}♡}
YoU
♡
ㅤㅤㅤㅤㅤㅤ