Question

at a given instant the speed of a scooter is 54km/h and after 10sec. it become 18km/h calculate its acceleration assuming it to be constant

Answer 1

here you go ☆☆

▪u = 54 km/h = > 15m/s
▪v = 18 km/h => 5 m/s
▪t = 10 s

as we know,

▪$a = \frac{v - u}{t}$

▪$a = \frac{5 - 15}{10}$

▪a = -10/10

▪$a = -1m/s^2$

hope it helps:)

Answer 2

Here, u= 54km/h which is equal to 15m/s.,
v= 18km/h= 5 m/ s.
T= 10 s
from 1st equation of motion ,
v=u+at,. ( v-u )/T = a
( 5-15)/10= a
so a= -1 m/ s²