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At a given place, a mercury barometer records a
pressure of 0.70 m of Hg. What would be the
height of water column if mercury in barometer is
replaced by water ? Take R.D. of mercury = 13-6.
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Relative Density of Hg = 1.36
= 1.36 × 10^3 kgm^-3
Acceleration due to gravity = 9.8 ms ^ -2
Hight of mercury column = 0.70 m
Pressure = hpg
Let him be the hight of the water column
= h × 10^3 × 9.8
h = 9.52
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