Question

At a given temperature, the pressure of a gas reduces to 75 percent of its initial value and the volume increases by 40 percent of its initial value. Find this temperature if the initial temperature was minus 10 degree celsius?

Answer 1

Hi friend ,

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Apply P1V1/T1 = P2V2/T2

let P1 = p and V1 = v

P2 = 3p/ 4
V2 = V + V*40 / 100

V2= 7v / 5

T1 = 273 - 10 = 263k
T2 = ?

P*V / 263 = ( 3p/ 4 ) ( 7v / 5 )

T2 = 21 * 263 / 20

T2 = 276.15

T2 = 276.15 - 273 = 3.15 ° C

.....i hope it helps you


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Answer 2

Answer:

3.15°C

Explanation:

see the picture