Question

at a height 0.4 m from the ground the velocity of a projectile in vector form is V=(6i+2j)m/s the angle of projection from horizontal is

Answer 1

Answer:

Explanation:

At a height 0.4m from the ground the velocity of a projectile in vector form is →v=(6ˆi+2ˆj)ms-1. The angle of projection is. tanθ=uyux=2√36=1√3⇒θ=30∘