Question

At a hydroelectric power plant, the water pressure head is at a height of 300 m and the water flow available is 100 m3s–1. If the turbine generator efficiency is 60%, estimate the electric power available from the plant (g = 9.8 ms–2 ).

Answer 1

Hii Dear,

◆ Answer -

Available power = 1.764×10^8 W

● Explanation -

# Given -

h = 300 m

V = 300 m^3/s

η = 60% = 0.6

# Solution -

Hydroelectric power by the plant is calculated as -

Power = F × v

Power = P × A × v

Power = ρgh × V

Substitute values,

Power = 1000 × 9.8 × 300 × 100

Power = 2.94×10^8 W

Actual power available is given by -

Available power = η × power

Available power = 0.6 × 2.94×10^8

Available power = 1.764×10^8 W

Thanks dear...