Question

At a local pet store, Shirley noticed that about four out of five customers who bought pets chose goldfish. Shirley wants to know the estimated probability that three randomly selected customers buying pets would not buy goldfish. How could Shirley design a simulation for this scenario? A. She could roll a six-sided die three times. On the die, numbers 1 to 3 represent customers who buy goldfish and 4 to 6 represent customers who don’t buy goldfish. B. She could spin a spinner divided into nine equal sections three times. On the spinner, four sections represent customers who buy goldfish and five sections represent customers who do not buy goldfish. C. She could spin a spinner divided into five equal sections three times. On the spinner, four sections represent customers who buy goldfish and one section represents customers who do not buy goldfish. D. She could use a random number generator to generate a set of three numbers from 0 to 9. The numbers 0 to 4 represent customers who buy goldfish, and 5 to 9 represent customers who do not buy goldfish. E. She could use a number generator to generate a set of five numbers from 0 to 3. The numbers 0 to 2 represent customers who buy goldfish, and 3 represents customers who do not buy goldfish.

Answer 1

Answer:

C.

Explanation:

Answer D is absolutely nonsensical, E doesn't work, B gives you a wrong answer just like E, so that leaves A and C. A is 50%, but 50% would have had to be at least 2 people. So that leaves C.

Answer 2

Answer:

The correct answer is option C.

Explanation:

Shirley was capable of revolving a spinner with five equal portions three times. Four parts on the spinner indicate customers who purchase goldfish, while one section symbolises those who do not. In this way she can estimate the probability of three randomly selected customers buying pets would not buy goldfish. Answer D is completely illogical, answer E is impossible, answer B provides an erroneous response similar to answer E, leaving only options A and C. A is $50$%, but $50$% would have required at least two individuals. That only leaves C.

In this way, we go with option C to get the required estimated probability.

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