At a metro station, a girl walks up a stationary escalator in
time t₁. If she remains stationary on the escalator, then the
escalator take her up in time t₂. The time taken by her to
walk up on the moving escalator will be
(a) t₁ + t₂/2
(b) t₁ t₂/t₂ - t₁
(c) t₁ t₂/t₂ + t₁ (d) t₁ – t₂
Answers
Answer:
Explanation:
et speed of girl on stationary escalator =V
g
=(V
1
)
speed of only escalator =V
e
=(V
2
)
slant distance =d
Now, time to go up when escalator is stop, t
g
=
V
g
d
=(=t
1
)
⇒V
g
=
t
g
d
time req. to go-up when girl stops & escalator moves, t
e
=
V
e
d
(=t
2
)
⇒V
e
=
t
2
d
Now, when both girl & escalator moves up,velocity of girl with respect ot ground =V
g
+V
e
Time taken, t=
V
g
+V
e
d
=
t
1
d
+
t
2
d
d
t=
t
2
+t
1
t
1
t
2
Answer:
(c) t₁ t₂/t₂ + t₁ is answer dear friend