Question

at a particular examination, sam got 16 more marks than john, who got 10%(of total marks) less than adam. also adam scored 2%(of total marks) more than peter, if peter had a score of 500 out of 600, what percentage of marks did sam get?

Answer 1

Step-by-step explanation:

Sam scored 78%. (seventy-eight percentage.)

Answer 2

Given:

At a particular examination,

Sam got 16 more marks than john

John got 10% (of total marks) less than Adam

Adam scored 2%(of total marks) more than peter

Peter had a score of 500 out of 600.

To find :

The percentage of marks did Sam get.

Solution:

Step 1 of 2:

Peter had a score of 500 out of 600.

Adam scored 2%(of total marks) more than peter,

Therefore,

2%(of total marks) more than peter = 500 + ( $\frac{2}{100}$ × 500 )

Total mark of Adam = 500 + 10

Total mark of Adam = 510 out of 600

John got 10% (of total marks) less than Adam

Therefore,

10% (of total marks) less than Adam = 510 - ( $\frac{10}{100}$ × 510 )

Total mark of John = 510 - 51

Total mark of John = 459 out of 600

Step 2 of 2:

Sam got 16 more marks than John,

Total marks of John is 459

Therefore, total marks of Sam = 459 + 16

Total marks of Sam = 475 out of 600

The percentage of Sam's marks = $\frac{475}{600}$ × 100

The percentage of Sam's marks = 79.17%

Final answer:

The percentage of marks did Sam got is 79.17%.