At a particular time suns altitude is 30 degrees. The length of shadow of vertical tower is 45 m. Calculate height of tower
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Draw a triangle ABC such that AB is the tower and BC is the length of the shadow.
∠B=90°
∠C=30°
tan 30°=1/√3=AB/BC
AB√3=BC
BC=45 m
So AB= BC/√3
On rationalising,
AB=(BC√3)/3
AB= (45√3)/3
AB=15√3 m
∴Height of tower is 15√3 m
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