Question

at a particular time the shadow of a pole and a tower are 26 m and 39m respectively. if the height of the pole is 34m what is the height of tower.​

Answer 1

Answer:

pls mark as brainiest

Step-by-step explanation:

at any time the heights of pole and their shadows are proportional to each other

so

h1/h2=s1/s2

34/h2=26/39=2/3

34/h2=2/3

17/h2=1/3

h2=51

Answer 2

Answer:

Step-by-step explanation:

Distance between point of observation and foot of tower = 20 m = BC

Angle of elevation of top of tower = 60∘=Θ

Height of tower H = AB

Now from fig ABC

ΔABC is a right angle triangle

1tanΘ=oppositeside(AB)Adjacentside(BC)

i.e tanC=ABBC

AB = 20 tan60∘

H = 20×3–√

= 203–√

∴heightofthetower