at a particular time the shadow of a pole and Tower are respectively 20 m and 40 m if the height of the tower is 48 metre find the height of the pole
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x²=48²+40²
x²=2304+1600
x²=3904
x=√3904
x=62.5m
height²=(62.5)²-(20)²
h²=3904-400
h²=3504
h=√3504
h=59.2m
x²=2304+1600
x²=3904
x=√3904
x=62.5m
height²=(62.5)²-(20)²
h²=3904-400
h²=3504
h=√3504
h=59.2m
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