Question

At a party, 60% were women. 35% of the women were wearing watches. Chosen at random for a lucky draw, what is the probability that the
winner would be a woman wearing a watch?
O 95/100​

Answer 1

Answer:

95/100

Step-by-step explanation:

Answer 2

The probability of women wearing watches at the party is 58.3%

Given:

Let us consider the probability of women to be P(A) and the probability of women wearing a watch to be P(A∩B), then their respective values are,

P(A) = 60%

P(A∩B) = 35%

To Find:

The probability that the winner would be a woman wearing a watch at the party

Solution:

By Conditional Probability, it is given that,

P(B|A) = P(B∩A)/P(A)

On substituting the values of P(A) and P(A∩B) we get,

P(B|A) = 0.35/0.65

          = 0.583

P(B|A) = 58.3%

Therefore, by conditional probability the probability of the winner would be a woman wearing a watch is 58.3%

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