Question

At a place dip angle is known to be 45°. The apparent dip when dip circle is placed at an angle of 60° with
the magnetic meridian will be

(1) tan°^-1 (2)
(2) tan^-1(1/2)
(3) tan^-1 (
$\sqrt{2}$
)

(4) tan^-1(1/
$\sqrt{2}$
)​

Answer 1

Answer:

Let δ  

1

​  

 be the angle of dip when dip circle is in magnetic meridian

tanδ  

1

​  

=  

H

V

​  

 

The dip circle when makes an angle θ , horizontal component of the earth's magnetic field is Hcosθ

The angle of dip when dip circle makes an angle with the  magnetic meridian is,

tanδ  

1

​  

=  

Hcosθ

V

​  

 

tanδ  

1

​  

=  

cosθ

tanδ

​  

 

tanδ  

1

​  

=  

2

​

Explanation: