At a place, the horizontal component of earth’s magnetic field is B and angle of dip is 60°. What is the value of horizontal component of the earth’s magnetic field at equator? [Delhi 2017]
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- The horizontal component of electric field is given by B=Be cos (o)
- o is angle of dip
- Be is teh net magnetic field
- At o is 60°
- B=Be cos 60°
- B=Be ( 1/2)
- Be= 2B
- here Bis BH
- Now horizontal component at equator
- BH= Becos ( o)
- angle of dip at equator is 0
- BH= Be cos (0)=Be=2B
- BH=2B
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The horizontal component of the earth's magnetic field at a place is b and angle of dip 60 degree what is the value of horizontal component of the earths magnetic field at a equator
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