Question

at a place, the magnitude of the horizontal components and total strength of the magnetic field of the earth are 0.3G and 0.6G respectively, the value of angle of dip at this place will be
a. 60
b. 45
c. 30
d. 0
degrees ​

Answer 1

Given that,

Horizontal component of magnetic field = 0.3 G

Total strength of magnetic field = 0.6 G

We need to calculate the vertical component

Using formula of vertical component

$B_{v}=B_{t}-B_{h}$

Put the value into the formula

$B_{v}=0.6-0.3$

$B_{v}=0.3\ G$

We need to calculate the value of angle of dip at this place

Using formula of angle of dip

$\tan\theta=\dfrac{B_{v}}{B_{h}}$

Where, $B_{h}$ = Horizontal component of magnetic field

$B_{v}$ = Vertical component of magnetic field

Put the value into the formula

$\tan\theta=\dfrac{0.3}{0.3}$

$\theta=\tan^{-1}\dfrac{0.3}{0.3}$

$\theta=45^{\circ}$

Hence, The value of angle of dip at this place will be 45°.

(b) is correct option.