Question

At a place, the value of g is less by 1% than its value on the surface of the Earth (Radius of Earth, R=6400km). The place is:

a) 64km below the surface of earth
b) 64km above the surface of earth
c) 30km above the surface of the earth
d) 32km below the surface of the earth.

Answer 1

Answer:

a)64km below the surface of earth.....

Explanation:

Let acceleration due to gravity at a place be gd. If g is acceleration due to gravity at the surface

then,

gd=(1-d/R)

0.99g=(0.01)

d/R =(0.01)

d=0.01×6400=64km below the surface of earth

hope it helps you.....

Answer 2

Answer:

a)64km below the surface of the earth

Explanation:

Let acceleration due to gravity at a place be gd. If g is the acceleration due to gravity at the surface

then,

gd=(1-d/R)

0.99g=(0.01)

d/R =(0.01)

d=0.01×6400=64km below the surface of earth