Question

At a place true dip is 45° and apparent dip is 60°. If the plane of dip circle is rotated by 90°, the dip shown by it will be?

Answer 1

Thus the value of angle of dip is σ2 = 51°

Explanation:

We are given that:

• σ1 = 60°
• σ = 45°
• Angle of rotation =  90°

Solution:

σ2 = ?

cot^2 (σ1)  = cot^2 ( σ) + cot^2 (σ2)

σ2 = cot^-1 ( √cot^2 σ + cot^2σ1

σ2 = cot^-1 ( √ 1^2 - ( 1 /√3)^2

σ2 = cot^-1 ( √ 0.67 )

σ2 = cot^-1 ( 0.816)

σ2 = 51°

Thus the value of angle of dip is σ2 = 51°

Answer 2

I hope it's help you

please mark as Brainliest.