Science, asked by anilkumarak9843, 1 year ago

At a place where the acceleration due to gravity is 10 M per second square a force of 5 kg-wtact act on a body of mass 10 kg initially at rest the velocity of the body after 4 second is

Answers

Answered by JunaidMirza
85
F = 5 kgwt = 5 kg × 10 m/s² = 50 N

a = F / m
= 50 N / (10 kg)
= 5 m/s²

v = u + at
= 0 + (5 m/s² × 4 s)
= 20 m/s
Velocity of body after 4 seconds is 20 m/s
Answered by kingofself
0

Velocity of body after 4 seconds is 20 m/s .

Explanation:

Forces given as 5 kgwt. this can be converted into Newton 5 kg × 10 m/s² = 50 N  

                                       a = \frac{F}{m}

we know the relation between mass force and acceleration in the form of formula applying the value we get

= \frac{50N}{10 kg}

                         = 5 m/s²

applying Newton's first law of motion

                         v = u + at

to find out the value of  final velocity  knowing that initial velocity is zero

= 0 + (5 m/s² × 4 s)

we get

= 20 m/s

To Learn more:

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