At a place where the acceleration due to gravity is 10 M per second square a force of 5 kg-wtact act on a body of mass 10 kg initially at rest the velocity of the body after 4 second is
Answers
a = F / m
= 50 N / (10 kg)
= 5 m/s²
v = u + at
= 0 + (5 m/s² × 4 s)
= 20 m/s
Velocity of body after 4 seconds is 20 m/s
Velocity of body after 4 seconds is 20 m/s .
Explanation:
Forces given as 5 kgwt. this can be converted into Newton 5 kg × 10 m/s² = 50 N
a =
we know the relation between mass force and acceleration in the form of formula applying the value we get
= \frac{50N}{10 kg}
= 5 m/s²
applying Newton's first law of motion
v = u + at
to find out the value of final velocity knowing that initial velocity is zero
= 0 + (5 m/s² × 4 s)
we get
= 20 m/s
To Learn more:
A body of mass 2 kg moving on a horizontal surface with initial velocity of 4 metre per second comes to rest after two seconds if one wants to keep this body moving on the same surface with a velocity of 4 metre per second the force required is
https://brainly.in/question/3921210
A constant force acts on an object of mass 5 kg for a duration of 2 seconds. It increases the object's velocity from 3 m/s to 7 m/s. Find the magnitude of the applied force. Now if the force were applied for a duration of 5 s what would be the final velocity of the object????????
https://brainly.in/question/49255