at a point 20m above the level of water of a lake, the angle of elevation of a cloud is 30° The angle ofdepression of the reflection of the cloud in the lake is 60° Find the height of cloud above
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SOLUTION:-
Given:
At a point 20m above the level of water of a lake, the angle of elevation of a cloud is 30°.
The angle of depression of the reflection of the cloud in the lake is 60°.
To find:
The height of the cloud.
Explanation:
Let BE be the surface of the lake. Suppose C be the position of the cloud & C be its reflection in the lake.
Then, AB = 20m.
•Assume CD= R m
•CE= C'E = (R +20)m
In ∆ACD,
tan30° = CD/AD
=) 1/√3 = R/AD
=) AD= R√3...............(1)
&
sin30° = CD/AC
=) 1/2 = R/AC
=) AC= 2R...................(2)
In ∆ADC',
tan60° = C'D/AD
=) √3 = (R+20)+20/AD
=) AD= (R+40)/√3.............(3)
From equation (2)& (3), we get;
=) R√3 = (R+40)/√3
=) 3R = R +40
=) 3R -R =40
=) 2R = 40
=) R= 40/2
=) R= 20m
Thus,
The height of the cloud is 20m.
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