At a point A, 20m above the level of water in a lake, the angle of elevation of a cloud is 30 degree. The angle of depression of the top of first pole as seen from the top of second pole is 30 degree. If the height of the first pole is 24m, find the height of the second pole.(use √3=1.732)
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Answer:
tan30
0
=
AD
EC
=
3
1
(ED=h)
⇒AD=h
3
---------------(1)
tan60
0
=
AD
FD
=
3
FD=h+40
AD=
3
h+40
----------------(2)
h
3
=
3
h+40
3h=h+40
2h=40
h=20m
EC=h+20=20+20=40m
Hence, the height of the cloud from the surface is 40cm.
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