Physics, asked by darshitbharti14, 11 months ago

At a point due to a point charge electric field intensity is 32 joules per coulomb and potential is 16 Joules per coulomb. calculate magnitude of charge and distance from point of observation

Answers

Answered by nibu4ever
5

Electric field intensity must be 32 N/C

PotentialV=16J/C

Distance=V/E=0.5 m


darshitbharti14: Can you show me the calculations ?
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