At a prayer meeting, the disciples sing JAI-RAM JAI-RAM. The sound amplified by a loudspeaker comes back after reflection from a building at a distance of 80 m from the meeting. What maximum time interval can be kept between JAI-RAM and the next JAI-RAM so that the echo does not disturb a listener sitting in the meeting. The speed of sound in air is 320 m/s.
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Answered by
4
Answer ⇒ 0.5 seconds.
Explanation ⇒
The maximum time interval will be the time of speaking JAI-RAM and the echo coming back after reflection.
Now, The sound waves will travel a distance 2 × 80 m = 160 m.
Also, The speed of the sound V =320 m/s.
Hence the required time = 2d/v
= 160/320 s
= 0.5 s
Hence, the time required is 0.5 seconds.
''JAI RAM.''
''Hope it helps.''
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0
Answer:
Answer ⇒ 0.5 seconds.
Explanation ⇒
The maximum time interval will be the time of speaking JAI-RAM and the echo coming back after reflection.
Now, The sound waves will travel a distance 2 × 80 m = 160 m.
Also, The speed of the sound V =320 m/s.
Hence the required time = 2d/v
= 160/320 s
= 0.5 s
Hence, the time required is 0.5 seconds.
Explanation:
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