Question

At a pressure of 405 kPa and a temperature of 200 K, the volume of a gas is 6.00 cm3. At what pressure will the new temperature and volume be 300 K and 4.00 cm3

Answer 1

Answer:

let p be pressure, v be volume and t be temperature

p1 = 405 kPa       p2 = ?

t1 = 200 K            t2 = 300 K

v1 = 6 cm3           v2 = 4 cm3

p1 x v1 / t1 = p2 x v2 / t2

405 x 6 / 200 = p2 x 4 / 300

p2 = 405 x 6 x 300 /200 x 4

p2 = 911.25 kPa