At a sale, 120 watches were sold the first day, and one-fourth of the remaining the next day. There were then 210 watches left. The number of watches originally put on sale was?
Answers
Answered by
3
Hey!!!!
@Bansal here
______________
let the original number of watches be x
Then according to the question
=> 120 + 1/4(x - 120) + 210 = x
=> 330 + (x - 120)/4 = x
=> 330 = x - (x - 120)/4
=> 330 = (4x - x + 120)/4
=> 3x + 120 = 1320
=> 3x = 1200
=> x = 400
Thus originally 400 watches were kept for sale
___________
Hope this helps ✌️
Legally Good Morning
@Bansal here
______________
let the original number of watches be x
Then according to the question
=> 120 + 1/4(x - 120) + 210 = x
=> 330 + (x - 120)/4 = x
=> 330 = x - (x - 120)/4
=> 330 = (4x - x + 120)/4
=> 3x + 120 = 1320
=> 3x = 1200
=> x = 400
Thus originally 400 watches were kept for sale
___________
Hope this helps ✌️
Legally Good Morning
angleranip6k6rd:
i think you have to - 120 from 1320 then divide by 3 gives us 400
oh yes
hmm
there you go
correvt answer is 400
hmmm
you can see my answer
ok
ok Rohit
hmm
Answered by
8
Hyy dear
Here is your answer
sale in first day = 120
and
let,
total watch be x
=> 120+1/4(x-120)+210 = x
=> 330+(x-120)/4 =x
=> 300 = x-(x-120)
=> 3x+120 = 1320
=> 3x = 1200
=> x = 400
thus, no. of original watch is 400
hope it's help u
mark as brainlist
Here is your answer
sale in first day = 120
and
let,
total watch be x
=> 120+1/4(x-120)+210 = x
=> 330+(x-120)/4 =x
=> 300 = x-(x-120)
=> 3x+120 = 1320
=> 3x = 1200
=> x = 400
thus, no. of original watch is 400
hope it's help u
mark as brainlist
thanku
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