At a shop the cost of a book is rupees 50 more than cost of a copy if the ratio of the cost of two books tto the cost of three copies is 5:6,then what is the cost of the book?
Answers
Answer:
let cost of the copy be x
and cost of the book be 50+x
so, according to the question
→ 2x/ 3(50+x) = 5/6
→ 2x/ 150+ 3x= 5/6
→ 6(2x) = 5(150+3x)
→ 12x= 750+ 15x
→ 15x-12x = 750
→ 3x= 750
→ x= 750/3
→ x= 250
As, the cost of the copy= 250 rs
Then cost of the book= 250+50 rs= 300rs
Step-by-step explanation:
PLEASE MARK AS BRAINLIEST
Given:
A Book and a copy where the cost of the book is 50 more than the cost of the copy.
The Ratio of cost of two books and cost of three copies is 5:6.
To Find:
Cost of a Single book.
Solution:
1. Given the cost of book is 50 more than the cost of the copy.
2. Let the cost of the book be x rupees and the cost of the copy be y rupees.
3. From statement 1 we can obtain a linear equation, i.e,
=> x = y + 50 ( Consider it as Equation 1).
4. It is further mentioned that the ratio of Cost of two books and Cost of three copies is 5:6
=> (2x/3y) = 5:6,
=> (2x/3y) = 5/6, ( a:b implies a/b).
=> 4x = 5y,
=> 4x - 5y = 0. (Consider it as Equation 2).
5. Substitute the value of x as y + 50 from equation 1 in equation 2,
=> 4 (y + 50) - 5y = 0,
=> 4y + 200 - 5y = 0,
=> -y + 200 = 0,
=> y = 200. (Cost of a Single copy)
6. Substitute the value of y as 200 in Equation 1,
=> x = 50 + 200,
=> x = 250. ( Cost of a Single Book).
Therefore, The cost of the book is 250 Rupees.