at a temperature of 23.4degree celsius . a ballon is filled with 2L air . what will be the value of the ballon at a temperature of 26.1degree celsius
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V1 = 2L
T2 = 26.1 + 273 = 299.1K
T1 = (23.4 + 273)K
T1 = 296.4K
• From Charles Law,
V1/T1 = V2/T2
V2 = V1T2/T1
V2 = 2L * 299.1K/296.4K
V2 = 2L * 1.009
V2 = 2.018L
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