Chemistry, asked by sutharbhavnad, 2 months ago

At a temperature of 273 Kelvin of ice and water the specific sizes are 1.089 and 1.0 mg, respectively. The molecular melting heat of ice at a temperature of 273 Kelvin and pressure of 1 bar is 6.025 kJ mol-. If melting 90 grams of ice at a temperature of 273 Kelvin and 1 bar of pressure becomes water of the same temperature, calculate the ∆H and ∆U values ​​for that process. (1 liter bar = 101.32 joules)


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Answers

Answered by bannybannyavvari
2

Answer:

and water vapour in the temperature range from 25°C (298 K) to 100°C (373 K) ... (368.5 K) and -273°C (0 K) respectively.

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