Question

At a temperature of 37 ° C and a pressure of 102.25 kPa, the volume of a specified mass of gas is 500. cm ^ 3 What is its volume in STP?​

Answer 1

The equations describing these laws are special cases of the ideal gas law, PV = nRT, where P is the pressure of the gas, V is its volume, n is the number of moles of the gas, T is its kelvin temperature, and R is the ideal (universal) gas constant.

Answer 2

$\frak{Given} \begin{cases} \sf Initial\: Pressure \:of\: gas \:(P₁)\: = \frak{102.25\:kPa} & \\ \\ \sf Initial \:Volume \:of \:gas\: (V₁)\: = \frak{500\:cm^3} & \\ \\ \sf Initial \:Temperature \:of \:gas\: (T₁) \:= \frak{37°C\:||\:310\:K} & \\ \\ \sf In \:STP \:(T)\: = \frak{273.15\:K} & \\ \\ \sf In \:STP\:(P)\: = \frak{100\:kPa}& \end{cases}$

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Here, we are asked to find Volume in STP.As we know the formula given :-

⠀$\sf \green { \dfrac{P_1V_1}{T_1} =\dfrac{PV}{T}}$

Now,for getting our required answer we have to put the values. So, let's start!

$\sf :\implies \dfrac{P_1V_1}{T_1} =\dfrac{PV}{T}$

$\sf :\implies \dfrac{102.25\times 500}{310} =\dfrac{100\times V}{273.15}$

$\sf :\implies \red {V = 450.23\:cm^3 }$

• Hence,The volume of the gas (in STP) is 450 cm cube.

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