Math, asked by vikky156, 1 year ago

- At a village trade fair a man buys a horse and a camel together for Rs 51,250. He sold the horse at a profit of 25 % and the camel at a loss of 20 %. If

he sold both the animals at the same price, then the cost price of the cheaper animal was R​

Answers

Answered by abhi569
9
Answer:
Cost of price of cheaper animal is Rs 20,000.

Step-by-step explanation:
Let the cost price of horse be Rs a and cost price of camel be Rs (51250 - a).

According to the question :
He sold the horse at a profit of 25% and the camel at a loss of 20%. Also, he sold both the animals at same price.

→ Selling price of horse = Selling price of camel

→ Cost price of horse + Profit = Cost price of camel + horse

→ a + 25% of a = (51250 - a) - 20% of (51250 - a)

→ a + 0.25a = (51250 - a) - 0.2(51250 - a)

→ 1.25a = 0.8(51250 - a)
→ 1.25a + 0.8a = 0.8(51250)
→ 2.05a = 41000
→ a = 20000
Therefore,
→ cost price of camel = Rs (51250 - 20000) = Rs 31250.

Hence, horse is cheaper than camel
And cost of price of horse is Rs 20,000.
Answered by avman08
0

Answer:

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