Question

- At a village trade fair a man buys a horse and a camel together for Rs 51,250. He sold the horse at a profit of 25 % and the camel at a loss of 20 %. Ifhe sold both the animals at the same price, then the cost price of the cheaper animal was R​

Answer 1

Answer:

i dont know the answer if you know answer me

Answer 2

Answer:

20,000

Step-by-step explanation:

We know profit % = (SP - CP) * 100/ CP

Therefore CP * (100 + P%) / 100 = SP

Loss% = (CP - SP) *100 / CP

Therefore CP * (100 - Loss%) / 100 = SP

Let CP of Horse = x, therefore CP of the Camel = 51250 - x

SP of Horse = x * 125 / 100 = 1.25x

SP of Camel = (51250 - x) * 80 / 100 = 0.8(51250 - x) = 41000 - 0.8x

Since SP of Horse = SP of Camel

Therefore, 1.25x = 41000 - 0.8x

Therefore 2.05x = 41000

x = 20000

CP of Horse = 20,000 and CP of Camel = 51250 - 20000 = 31,250

CP of the cheaper Animal = 20,000