At ABB China college of 2017, Shivam, a new candidate has taken 10 courses, earning grades
P (worth 4 points each), Q (worth 3 points each) and R (worth 2 points each). His grade point
average is 3.2, and if the course in which he get R's were deleted, his GPA in the remaining
courses would be 3.333. How many P's, Q's and R's did he get?
Answers
Given : taken 10 courses, earning grades P (worth 4 points each), Q (worth 3 points each) and R (worth 2 points each).
His grade point average is 3.2.
if the course in which he get R's were deleted, his GPA in the remaining
courses would be 3.333
To Find : How many P's, Q's and R's did he get?
Solution:
Let say P's = x
and Q's = y
then R's = 10 -(x + y)
Score = (4x + 3y + 2(10 - x - y)) / 10 = 3.2
=> 4x + 3y + 20 -2x - 2y = 32
=> 2x + y = 12
R's were deleted ( 3.333 = 10/3)
=> (4x + 3y)/(x + y) = 10/3
=> 12x + 9y = 10x + 10y
=> 2x = y
2x + y = 12
=> y + y = 12
=> 2y = 12
=> y = 6
=> x = 3
P's = 3
Q's = 6
R's = 10 -(3 + 6) = 1
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Answer:
P's = 3
Q's = 6
R's = 10 -(3 + 6) = 1
Step-by-step explanation:
Let say P's = x
and Q's = y
then R's = 10 -(x + y)
Score = (4x + 3y + 2(10 - x - y)) / 10 = 3.2
=> 4x + 3y + 20 -2x - 2y = 32
=> 2x + y = 12
R's were deleted ( 3.333 = 10/3)
=> (4x + 3y)/(x + y) = 10/3
=> 12x + 9y = 10x + 10y
=> 2x = y
2x + y = 12
=> y + y = 12
=> 2y = 12
=> y = 6
=> x = 3
P's = 3
Q's = 6
R's = 10 -(3 + 6) = 1
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