Question

@ Abody starts from rest and gain a velocity 20m/s in 5 sec. Find the acceleration
and distance covered​

Answer 1

Answer:

the accelaration of the body is 4m/S2 and the distance covered by the body is 50m

Answer 2

Explanation:

u=0

v=20m/s

t=5 sec

acceleration =v-u/t

=20-0/5=4 m/s^2

Distance

S=ut+1/2at^2

=0*5+1/2*4*5^2

=0+50

=50 m

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