at an election contested by two candidates a candidate got 20% of total votes and defeated by another person by a majority of 2400 votes find the number of votes polled by the winning candidate.
Answers
Answered by
4
ANSWER :-
2400 votes
Explaination :-
Let the total votes be x .
Majority = 2400 votes
Votes by candidate who loses = 20 % of x
=> 20 x / 100
According to Question
x - 20 x / 100 = 2400
100 x - 20 x / 100 = 2400
80 x / 100 = 2400
80 x = 2400 × 100
80 x = 240000
x = 240000 / 80
x = 3000
So , Here We Get ,
Total Votes = 3000 votes
Votes polled by Candidate who loses :-
=>20 % of total votes
=>20 % of 3000
=>20 / 100 × 3000
=>600
Votes polled by winning candidate :-
=>Total votes - Votes by opposite candidate
=>3000 - 600
=>2400
2400 votes
Explaination :-
Let the total votes be x .
Majority = 2400 votes
Votes by candidate who loses = 20 % of x
=> 20 x / 100
According to Question
x - 20 x / 100 = 2400
100 x - 20 x / 100 = 2400
80 x / 100 = 2400
80 x = 2400 × 100
80 x = 240000
x = 240000 / 80
x = 3000
So , Here We Get ,
Total Votes = 3000 votes
Votes polled by Candidate who loses :-
=>20 % of total votes
=>20 % of 3000
=>20 / 100 × 3000
=>600
Votes polled by winning candidate :-
=>Total votes - Votes by opposite candidate
=>3000 - 600
=>2400
Answered by
16
Answer:
3200
Step-by-step explanation:
The loosing candidate has 20% of total votes.
So the winning candidate has 100% - 20% = 80% of total votes.
The majority is 80% - 20% = 60% of votes.
But its given in the question that the majority is 2400 votes.
Thus 60% = 2400
So 1% = 2400/60 = 40
Winning candidate votes = 80% = 80 * 40 = 3200
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