at an instant length of images root 3 times that of height of pole find the angle of elevation of the Sun..
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Consider the height of tower be h
∴ height of shadow =√3h .
In a triangle ABC,
tan ∠ACB = h / √3h
tan ∠ACB = 1 / √3
∠ACB = 30°.
Therefore, angle of elevation is 30°.
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∴ height of shadow =√3h .
In a triangle ABC,
tan ∠ACB = h / √3h
tan ∠ACB = 1 / √3
∠ACB = 30°.
Therefore, angle of elevation is 30°.
Please mark me as brainliest.
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thanks a lot
thanks a lot
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I hope this helps you
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hi yes it helped me a lot thanks a lot
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