at
and the y-axis at Q. The ratio PA : AQ is:
The line through A(3, 1) perpendicular to x - 4y = 8 meets the x-axis :
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Answer:
Given:-
Mass of automobile (m) = 1500 kg.
Acceleration (a) = –1.7 ms^{–2}
–2
To find:-
Force between the vehicle and the road
Solution:-
We know that,
Force (f) = ma
= (1500 kg) (–1.7 ms)^{–2}
–2
= –2550 N.
Thus, force between the vehicle and the road if the vehicle is to be stopped with a negative acceleration of 1.7 ms^{–2}
–2
is –2550 N.
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