Question

At any angle if the give pair of forces acts on a particle then the following can magnitude of8n

Answer 1

Explanation:

The resultant of two vectors:

P

and

Q

is given by

R=

P

2

+Q

2

+2PQcosθ

where, P and Q are magnitudes of two vectors and θ is the angle between two vectors.

Here θ=? P=8N Q=15N R=17N

Therefore,

17=

8

2

+15

2

+2×8×15cosθ

289=64+225+240cosθ

289=289+240cosθ

289−289=240cosθ

cosθ=0

cosθ=cos90

θ=90

0