Question

@ aravind
plz give me the answer if u know.....​

Answer 1

$\huge\underline\mathtt\color{red} Answer$

first of all we factorise :-

3x²-4x+1 3x² -4x + 13x²−4x+13x²−4x+1

=3x² -3x -x +1=3x²−3x−x+1

=3x( x -1) -1(x -1)=3x(x−1)−1(x−1)

=(3x -1)(x -1)=(3x−1)(x−1)

hence. (3x -1) and (x -1) are the factors of given polynomial .

so, x = 1/3 and 1 are the zeros of that polynomial.

hence, α = 1/3. and β = 1

=(3x -1)(x -1)=(3x−1)(x−1)

or α =

1 and β. = 1/31andβ.=1/3

you can choose any one in both

I choose α =

1. and β = 1/31.andβ=1/3

now,

let any unknown. polynomial. whose zeros are

α²/β and β²/αα²/βandβ²/α

α²/β = (1)²/(1/3) = 3α²/β=(1)²/(1/3)=3

β²/α = (1/3)²/1 = 1/9β²/α=(1/3)²/1=1/9

now, equation of unknown polynomial.

x²- ( sum of roots)x + product of roots

β²/α = (1/3)²/1 = 1/9β²/α=(1/3)²/1=1/9

= x²- ( α²/β + β²/α)x +(α²/β)(β²/α)=x²−(α²/β+β²/α)x+(α²/β)(β²/α)

put α²/β = 3 and β²/α = 1/9putα²/β=3andβ²/α=1/9

= x²- ( 3 +1/9)x + 3 × 1/9=x²−(3+1/9)x+3×1/9

= x² -28x/9 + 3/9=x²−28x/9+3/9

={ 9x² -28x + 3 }1/9=9x²−28x+31/9

hence, 9x² -28x + 3 is answer;!

bye didi...❤✨✌️⚡

will come bck after exams...

do reply @ the messages I sent u❤

Answer 2

Answer:

can you please answer my MATHS questions