Question

at
At a particular time, when the sun's altitude is
30°, the length of the shadow of a vertical tower is 45 m. calculate-
the height of the tower
the length of the shadow of the same tower when the suns altitude is 45 and 60
​

Answer 1

Answer:

hii

Step-by-step explanation:

I think the length is wrong in question

Answer 2

Answer:

During 30° = 45$\sqrt{3}$m

During 60° = 15$\sqrt{3}$m

During 45° = 45m

Step-by-step explanation:

Height of tower = 45m

tan ∅ = $\frac{O}{A}$

tan 30 = $\frac{45}{A}$

$\frac{1}{\sqrt{3} }$ = $\frac{45}{A}$

A = 45$\sqrt{3}$m

∴ The length of the shadow during 30° is 45$\sqrt{3}$m

Height of tower = 45m

tan ∅ = $\frac{O}{A}$

tan 60 = $\frac{45}{A}$

$\sqrt{3}$ = $\frac{45}{A}$

A = $\frac{45}{\sqrt{3} }$

A = $\frac{45\sqrt{3}}{\sqrt{3} . \sqrt{3} }$

A = $\frac{45\sqrt{3} }{3}$

A = 15$\sqrt{3}$cm

∴ The length of the shadow during 60° is 15$\sqrt{3}$m

Height of tower = 45m

tan ∅ = $\frac{O}{A}$

tan 45 =  $\frac{45}{A}$

1 =  $\frac{45}{A}$

A = 45m

∴ The length of the shadow during 45° is 45m

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