At certain position x potential energy of particle is 1/4th of its maximum value during oscillation. Its displacement from mean position should be
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Answered by
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Answered by
0
We have,
PE may =
2
1
ka
2
PE=
2
1
kx
2
According to question,
2
1
kx
2
=
4
1
.
2
1
kA
2
x=
2
a
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