Question

At certain temp. And total pressure of 10^5 pa iodine vapours contains 40% by volume of i atoms calculate kp for eq^m

Answer 1

Partial pressure of L atoms

$p1 = \frac{40}{100} \times p \: (total) \\ \\ = \frac{40}{100} \times 10 {}^{5} \\ \\ = 4 \times 10 {}^{4} \: \: \: pa$

Partial pressure of L2 molecules,

$p2 = \frac{60}{100} \times p (total) \\ \\ = \frac{60}{100} \times 10 {}^{5} \\ \\ = 6 \times 10 {}^{4} \: \: pa$

Now, for the given reaction,

$k_{p} = \frac{(p1) {}^{2} }{p2} \\ \\ = \frac{(4 \times 10 {}^{4}) { }^{2} \: pa {}^{2} }{ {}^{6 \times 10 {}^{4} \: pa \: } } \\ \\ = 2.67 \times 10 {}^{4} \: \: \: pa$

✌✌✌✌✌✌✌✌✌

#follow me