Question

At certain temperature, the following
reactions have the equilibrium constants as
shown below:
S(s)+O2(g)=SO2(g);
Kc=5x10522S(s)+302(g)=2503(g); Kc=1029
What is the equilibrium constant Kc for the
reaction at the same temperature?
2502(g)+O2(g)=2503(g)
(A) 2.5x1076
(B) 4x1023
(C) 4x10-77
(D) None of these
​

Answer 1

Answer:

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Explanation:

Equilibrium reactions depends upon the reaction equations

S

(S)

+O

2(g)

⇌SO

2(g)

;K

C

=5×10

52

2S

(S)

+3O

2(g)

⇌2SO

2(g)

;K

C

=10

29

The K

C

for the reaction is calculated as,

2SO

2(g)

+O

2(g)

⇌2SO

3(g)

By the equation,

2S+3O

2

⇌2SO

3

K

C

"

=

[O

2

]

3

[SO

3

]

2

By reversing the first eqaution and doubling the coefficient K

C

,

(K

C

,

)

−1

Multiply both side of the equation by K,

⇒2.5×10

76