Question

At certain temperature the Kw of D2O IS 10^-16M. THEN PH of pure D2O at that temperature is​

Answer 1

Answer:

8

Explanation:

We know,

[D+] [OD-] = Kw

=> [D+]² = 10^-16

=>[D+] = 10^-8

Now, pD = - log (D+)

= - log (10^-8)

= 8 Ans