Question

At constant 600cm3 contains hydrogen gas at a pressure of 304 cm Hg. What will be the pressure of hydrogen gas, when the vessel is connected to another vessel of 300cm3

Answer 1

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Answer 2

Answer:

Answer = 202.67cm of Hg.

Explanation:

now,

given,

P1 = 304 cm of Hg,

P2 = ?;

V1 = 600 cm³

V2 = 600 + 300 cm³

= 900 cm³

therefore,

by Boyle's law,

P1V1 = P2V2

304×600 = P2 ×300

$\frac{304 \times 600}{900} = p2$

by cancelling it,

P2 = 202.67cm of Hg.....

hope it helps you.