Physics, asked by adityatekari321, 1 year ago

At constant potential difference, the resistance of any electric circuit is halved, the value of heat produced will be ?​

Answers

Answered by mayankprasad111
11
H=V2/R t

R'= R/2


H'=V2/R/2 t

H'=2 V2/R t

H'= 2H
Answered by AadilPradhan
1

We know, H = (V^2/R) * t

Where H is the heat produced, V is the potential difference, R is the resistance of the circuit and t is the time parameter.

In this case, V is constant, R' = R/2

So, H' = (V^2/R') * t

Or, H' = 2*(V^2/R) * t

Or, H' = 2*H

Hence, the new value of the heat produced will be twice of the original heat produced.

Heat energy arises due to the movement of tiny particles called atoms, molecules or ions in solids, liquids and gases.

Heat energy can be transferred from one body to another

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